If sinA=\(\frac{4}{5}\), sinB=\(\frac{15}{17}\)

find the value of sin(A - B).

\(\frac{-13}{85}\)

sin(A - B) = sinA cosB - cosA sinB

= sinA = \(\frac{4}{5}\)=\(\frac{P}{H}\) (Triplet 3, 4, 5)

B = 3

= sinB = \(\frac{15}{17}\)=\(\frac{P}{H}\) (Triplet 8, 15, 17)

B = 8

Put in sin(A - B)

⇒ \(\frac{4}{5}\)×\(\frac{8}{17}\)-\(\frac{3}{5}\)×\(\frac{15}{17}\)

= \(\frac{32}{85}\)-\(\frac{45}{85}\)

= \(\frac{-13}{85}\)