If sinA=\(\frac{4}{5}\), sinB=\(\frac{15}{17}\)
find the value of sin(A - B).
Answer & explanation
Correct answer: option 2
sin(A - B) = sinA cosB - cosA sinB
= sinA = \(\frac{4}{5}\)=\(\frac{P}{H}\) (Triplet 3, 4, 5)
B = 3
= sinB = \(\frac{15}{17}\)=\(\frac{P}{H}\) (Triplet 8, 15, 17)
B = 8
Put in sin(A - B)
⇒ \(\frac{4}{5}\)×\(\frac{8}{17}\)-\(\frac{3}{5}\)×\(\frac{15}{17}\)
= \(\frac{32}{85}\)-\(\frac{45}{85}\)
= \(\frac{-13}{85}\)