The height of an equilateral triangle is $5\sqrt{3}\, cm$, then its area is:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $25\sqrt{3}\, cm^2$
The given height is $5\sqrt{3}$ cm.
For an equilateral triangle:
$h = \frac{\sqrt{3}}{2}a$
So,
$a = \frac{2h}{\sqrt{3}} = \frac{2 \times 5\sqrt{3}}{\sqrt{3}} = 10 \text{ cm}$
Now, area:
$\text{Area} = \frac{\sqrt{3}}{4}a^2 = \frac{\sqrt{3}}{4} \times 100 = 25\sqrt{3}\ \text{cm}^2$