Practicing Success
Find the domain of $f(x)=\sqrt{\cos^{-1}x-\sin^{-1}x}$ |
$[-1,\frac{1}{\sqrt{2}}]$ $[-1,-\frac{1}{\sqrt{2}}]$ $[-\frac{1}{\sqrt{2}},\frac{1}{\sqrt{2}}]$ $[-\frac{1}{\sqrt{2}},1]$ |
$[-1,\frac{1}{\sqrt{2}}]$ |
We must have $\cos^{-1}x≥\sin^{-1}x$ or $\frac{π}{2}-\sin^{-1}x≥\sin^{-1}x$ or $\frac{π}{2}≥2\sin^{-1}x$ or $\sin^{-1}x≤\frac{π}{4}$, but $-\frac{π}{2}≤\sin^{-1}x$ or $-\frac{π}{2}≤\sin^{-1}x≤\frac{π}{4}$ or $\sin(-\frac{π}{2})≤x≤\sin\frac{π}{4}$ (∵ $\sin x$ is increasing function in $[-\frac{π}{2},\frac{π}{2}]$) or $x∈[-1,\frac{1}{\sqrt{2}}]$ |