Find the domain of f(x)=√(cos^-1x-sin^-1x)

We must have $\cos^{-1}x≥\sin^{-1}x$

or $\frac{π}{2}-\sin^{-1}x≥\sin^{-1}x$

or $\frac{π}{2}≥2\sin^{-1}x$

or $\sin^{-1}x≤\frac{π}{4}$, but $-\frac{π}{2}≤\sin^{-1}x$

or $-\frac{π}{2}≤\sin^{-1}x≤\frac{π}{4}$

or $\sin(-\frac{π}{2})≤x≤\sin\frac{π}{4}$

(∵ $\sin x$ is increasing function in $[-\frac{π}{2},\frac{π}{2}]$)

or $x∈[-1,\frac{1}{\sqrt{2}}]$