If $(x+y): (x-y)=7: 3$, then find the ratio of $(x^2+ y^2): (x^2-y^2)$.
Answer & explanation
Correct answer: option 2
(x+y):(x-y) = 7:3
1) $(x+y)*(x-y) = 21k^2$
$x^2 - y^2 = 21k^2$ ......a
2) $(x+y)*(x+y) = 49 k^2$
$x^2 + y^2 + 2xy = 49 k^2$ .......b
3) $(x-y)*(x-y) = 9 k^2$
$x^2 + y^2 - 2xy = 9 k^2$ ...c
Equation b + c,
$2(x^2 + y^2) = 58 k^2$
$(x^2 + y^2) = 29 k^2$
$(x^2+ y^2): (x^2-y^2)$ = 29:21
The correct answer is Option (2) → 29 : 21