Practicing Success
A man travels a certain distance at 15km/h and returns to the starting point at 6km/h. The total time taken by him for the entire journey is 5\(\frac{1}{4}\) hours. The total distance (in km.) covered by him: |
35 \(\frac{45}{2}\) 45 40 |
45 |
When distance is same, then speed ∝ \(\frac{1}{time}\) Go Come Speed = 15 : 6 Time = 6 : 15 Total time ⇒ 6 + 15 = 21 ⇓×\(\frac{1}{4}\) \(\frac{21}{4}\) (given) Therefore, time taken to go = 6 × \(\frac{1}{4}\) = \(\frac{6}{4}\) Total Distance = 15km/hr × \(\frac{6}{4}\) × 2 = 45 km. |