A light bulb is rated as 100 W, 230 V and is connected to a 230 V ac source. The value of peak current is
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 0.61 A
Given:
Power, $P = 100\,W$
RMS voltage, $V_{rms} = 230\,V$
For an AC circuit with purely resistive load:
$P = V_{rms} I_{rms}$
⟹ $I_{rms} = \frac{P}{V_{rms}} = \frac{100}{230} = 0.435\,A$
Peak current:
$I_0 = \sqrt{2}\, I_{rms} = 1.414 \times 0.435 = 0.615\,A$
Final Answer: $I_0 = 0.62\,A$