The least non-negative remainder when 2^101 is divided by 5 is:

The correct answer is Option (3) → 2

$2^1\equiv 2,\;2^2\equiv 4,\;2^3\equiv 3,\;2^4\equiv 1\pmod 5$

$\text{Cycle length}=4$

$101\;\text{mod}\;4=1$

$2^{101}\equiv 2^1\equiv 2\pmod 5$

The least non-negative remainder is $2$.