The function f defined by $f(x)=\left\{\begin{matrix} ax+1 & if & x≤3\\bx+3 & if & x> 3\end{matrix}\right. $ is continuous at x = 3 if
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $a=b+\frac{2}{3}$
$f(3)=3a+1$
$\underset{x→3}{\lim}bx+3=3b+3$
so $3a+1=3b+3$
$a=b+\frac{2}{3}$