Practicing Success
Practicing Success
CUET Preparation Today
The function f defined by $f(x)=\left\{\begin{matrix} ax+1 & if & x≤3\\bx+3 & if & x> 3\end{matrix}\right. $ is continuous at x = 3 if |
$a=b-\frac{2}{3}$ $a=b+\frac{2}{3}$ $a=b-\frac{1}{3}$ $a=b+\frac{1}{3}$ |
$a=b+\frac{2}{3}$ |
The correct answer is Option (2) → $a=b+\frac{2}{3}$ $f(3)=3a+1$ $\underset{x→3}{\lim}bx+3=3b+3$ so $3a+1=3b+3$ $a=b+\frac{2}{3}$ |
