Practicing Success
The interval in which the function, f(x) = 7 – 4x – x2 is strictly increasing is |
(-∞, ∞) (–2, ∞) (-∞, -2) (-∞, -2) |
(-∞, -2) |
$f(x) = 7 - 4x - x^2$ $f'(x) > 0$ $f'(x)=\frac{d}{dx}(7 - 4x - x^2)$ {$\frac{d}{dx}x^n=nx^{n-1}$} $\frac{d}{dx}(c)=0$ $= 0-4-2x⇒-(4+2x)$ $-(4+2x)>0$ $4+2x<0⇒2x<-4$ $x<-2$ $x∈(-∞, -2) $ |