If θ is the angle between two vectors \(\vec{a}\) and \(\vec{b}\) then \(\vec{a}\).\(\vec{b}\) ≥0 only when-
Answer & explanation
Correct answer: option 3
Let θ is the angle between two vectors \(\vec{a}\) and \(\vec{b}\) then \(\vec{a}\) . \(\vec{b}\)≥0
Then, without loss of generality, \(\vec{a}\) and \(\vec{b}\)are non-zero vectors so that |\(\vec{a}\)| and | \(\vec{b}\) | are positive.
it is known that (\(\vec{a}\) .\(\vec{b}\)) =|\(\vec{a}\) |.|\(\vec{b}\) | cosθ
⇒ | \(\vec{a}\)|.|\(\vec{b}\) |cosθ ≥0
⇒ cosθ ≥0
⇒ 0 ≤ θ ≤ π/2
Hence \(\vec{a}\).\(\vec{b}\)≥0 when 0 ≤θ ≤ π/2