Find the equation of curve whose DE is :

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Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Differential Equations

Question:

Find the equation of curve whose DE is : x dy = (2x² + 1) dx; x$\neq $0

Options:

x = y² + log |x| + C

y = x² + log |x| + C

x = y² - log |x| + C

y = x² - log |x| + C

Correct Answer:

y = x² + log |x| + C

Explanation:

x dy = (2x² + 1) dx

dy = (2x² + 1) dx/x and then integrate to get :

y = x² + log |x| + C