Find the equation of curve whose DE is : x dy = (2x2 + 1) dx; x\(\neq \)0
Answer & explanation
Correct answer: option 2
x dy = (2x2 + 1) dx
dy = (2x2 + 1) dx/x and then integrate to get :
y = x2 + log |x| + C
Find the equation of curve whose DE is : x dy = (2x2 + 1) dx; x\(\neq \)0
Correct answer: option 2
x dy = (2x2 + 1) dx
dy = (2x2 + 1) dx/x and then integrate to get :
y = x2 + log |x| + C