Practicing Success
A balloon with mass ‘m’ is descending down with an acceleration ‘a’ (where a < g). How much mass should be removed from it so that it starts moving up with an acceleration ‘a’? |
\(\frac{2 ma}{g+a}\) \(\frac{2 ma}{g-a}\) \(\frac{ma}{g+a}\) \(\frac{ma}{g-a}\) |
\(\frac{2 ma}{g+a}\) |
Let up thrust of air be Fb then for downward motion mg – Fb = ma Let's assume that mass m' be removed from the balloon So when it start moving upward Fb - (m - m') g = (m - m')a m' = \(\frac{2ma}{g+a}\) |