Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Laws of Motion

Question:

A balloon with mass ‘m’ is descending down with an acceleration ‘a’ (where a < g). How much mass should be removed from it so that it starts moving up with an acceleration ‘a’?

Options:

\(\frac{2 ma}{g+a}\)

\(\frac{2 ma}{g-a}\)

\(\frac{ma}{g+a}\)

\(\frac{ma}{g-a}\)

Correct Answer:

\(\frac{2 ma}{g+a}\)

Explanation:

Let up thrust of air be Fb then for downward motion mg – Fb = ma

Let's assume that mass m' be removed from the balloon

So when it start moving upward

Fb - (m - m') g = (m - m')a

m' = \(\frac{2ma}{g+a}\)