Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Percentages

Question:

In an examination it is required to get a minimum of 340 marks in aggregate to pass. A student gets 244 marks and is declared failed by 12% of the total marks. What are the maximum aggregate marks a student can get?

Options:

1000

800

960

720

Correct Answer:

800

Explanation:

Passing marks  = 340

 A student secured = 244 

 Student failed by = 340 - 244  = 96 marks

ATQ,

12% of the total marks = 96

\(\frac{12}{100}\) ×  the total marks = 96

 Total marks = 96 ×  \(\frac{100}{12}\) = 800