Order and degree of the differential equation $\left[1+\left(\frac{dy}{dx}\right)^3\right]^{\frac{5}{4}}=\frac{d^2y}{dx^2}$ are :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → Order 2, degree 4
$\left[1+\left(\frac{dy}{dx}\right)^3\right]^{\frac{5}{4}}=\frac{d^2y}{dx^2}$
$⇒\left[1+\left(\frac{dy}{dx}\right)^3\right]^5=\left(\frac{d^2y}{dx^2}\right)^4$
Order 2, degree 4