Practicing Success
The general solution of the differential equation $\frac{dy}{dx}-\frac{y}{x}=x^2$ is : |
$y=\frac{x^3}{2}+C$, where C is a constant $y=\frac{x^3}{2}+Cx$, where C is a constant $y=\frac{x}{2}+Cx$, where C is a constant $y=\frac{x^3}{2}+Cx^2$, where C is a constant |
$y=\frac{x^3}{2}+Cx$, where C is a constant |
The correct answer is Option (2) → $y=\frac{x^3}{2}+Cx$, where C is a constant $\frac{dy}{dx}-\frac{y}{x}=x^2$ → eq. $I.F. = e^{-\int\frac{1}{x}dx}=e^{-\log x}=\frac{1}{x}$ multiplying eq with I.F. $\int\frac{1}{x}\frac{dy}{dx}-\frac{y}{x}dx=\int xdx$ $⇒\frac{y}{x}=\frac{x^2}{2}+C$ $⇒y=\frac{x^3}{2}+Cx$ |