Choose the correct ascending order of the particle according to their de-broglie wavelength,when they are accelerated by same potential

$H_1^3 < H_1^2 < H_1^1 < e$

$\text{De-broglie Wavelength }\lambda = \frac{h}{p} = \frac{h}{\sqrt{2mqV}}$

$\text{V and q is same for each particle}$

$\text{since }\lambda \text{ is inversely propotional to m}$

$\Rightarrow \text{De-broglie wavelength of }H_1^3 < H_1^2 < H_1^1 < e$