Practicing Success
In which of the following compounds, the oxidation number of iodine is fractional? |
\(IF_7\) \(I_3^–\) \(IF_5\) \(IF_3\) |
\(I_3^–\) |
The correct answer is option 2. \(I_3^–\). To determine in which compound the oxidation number of iodine is fractional, let's analyze each compound: Iodine can have a maximum oxidation state of +7 in \(IF_7\). Oxidation state of iodine in \(IF_7\) is \(+7\). It is not fractional. 2. \(I_3^–\) (Triiodide Ion): The triiodide ion (\(I_3^-\)) consists of three iodine atoms with a total charge of \(-1\). Oxidation state of iodine in \(I_3^-\): Each iodine atom has an oxidation state of \(-\frac{1}{3}\). This is fractional. 3. \(IF_5\) (Iodine Pentafluoride): Iodine in \(IF_5\) typically has an oxidation state of +5. Oxidation state of iodine in \(IF_5\) is \(+5\). It is not fractional. Iodine in \(IF_3\) typically has an oxidation state of +3. Oxidation state of iodine in \(IF_3\) is \(+3\). It is not fractional. Based on the analysis, the compound in which the oxidation number of iodine is fractional is: (2) \(I_3^–\) (Triiodide Ion) |