As per Bohr model, the minimum energy (in eV) required to remove an electron from the ground state of doubly ionized Li atom (Z = 3) is
Answer & explanation
Correct answer: option 4
$E=-Z^2 \times 13.6 eV=-9 \times 13.6 eV=-122.4 eV$
So ionisation energy = + 122.4 eV.