The hydrogen atom is excited from ground state to a state with the principal quantum number (n) = 4. The number of spectral lines in the emission spectra will be

6

The correct answer is Option (1) → 6

The number of spectral lines emitted when an electron falls from a level $n$ to lower levels is given by:

$\text{Number of lines} = \frac{n(n-1)}{2}$

Given $n = 4$:

$\text{Number of lines} = \frac{4 \cdot (4-1)}{2} = \frac{12}{2} = 6$

Number of spectral lines = 6