Let \(f\ :\ R \to \ R\) be the function defined by \(f(x)=x^2-6x+10\), then the range of f is
Answer & explanation
Correct answer: option 2
\(f(x)=x^2-6x+10\)
\(=(x-3)^2+1\)
As \((x-3)^2\geq 0\)
means \(f(x)\geq 1\)
Therefore, the range is \([1,\infty)\)