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Let \(f\ :\ R \to \ R\) be the function defined by \(f(x)=x^2-6x+10\), then the range of f is |
\(R\) \([1,\infty)\) \([6,\infty)\) \([10,\infty)\) |
\([1,\infty)\) |
\(f(x)=x^2-6x+10\) \(=(x-3)^2+1\) As \((x-3)^2\geq 0\) means \(f(x)\geq 1\) Therefore, the range is \([1,\infty)\) |
