CUET Preparation Today
If $f(x) =\int\limits_0^x(t+1) (e^t –1) (t – 2) (t + 4) dt$ then f(x) would assume the local minima at |
x = - 4 x = 0 x = -1 none of these |
x = -1 |
Here, $f'(x)= (x + 1) (e^x – 1) (x – 2) ( x + 4)$
Clearly x = -1 and x = 2 are the points of local minima. Hence (C) is the correct answer. |
