If $K+\frac{1}{K}+2=0$ and K < 0, the

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If $K+\frac{1}{K}+2=0$ and K < 0, then what is the value of $K^{10}+\frac{1}{K^{11}}$ ?

Options:

-1

Correct Answer:

Explanation:

$K+\frac{1}{K}+2=0$ and K < 0, then what is the value of $K^{10}+\frac{1}{K^{11}}$

= $K+\frac{1}{K}=-2$

= put k = -1

$K^{10}+\frac{1}{K^{11}}$ = $-1^{10}+\frac{1}{-1^{11}}$ = 0