CUET Preparation Today
If $K+\frac{1}{K}+2=0$ and K < 0, then what is the value of $K^{10}+\frac{1}{K^{11}}$ ? |
1 0 -1 2 |
0 |
$K+\frac{1}{K}+2=0$ and K < 0, then what is the value of $K^{10}+\frac{1}{K^{11}}$ = $K+\frac{1}{K}=-2$ = put k = -1 $K^{10}+\frac{1}{K^{11}}$ = $-1^{10}+\frac{1}{-1^{11}}$ = 0 |
