Given below are two parallel lines.

$\frac{x+1}{2} = \frac{y-2}{3} = \frac{z-1}{-j}$ and $\frac{x+3}{k} = \frac{y+1}{-2} = \frac{z+3}{-2}$. Find the values of $k$ and $j$.

$k = -4/3, j = -3$

The correct answer is Option (1) → $k = -4/3, j = -3$ ##

We can write that the lines are parallel and so

$\frac{2}{k} = \frac{3}{-2} = \frac{-j}{-2}$

When solving the above equation, we get

$k = -\frac{4}{3} \text{ and } j = -3$