A moving coil galvanometer has a resistance of 40 Ω. It gives a full scale deflection with a current of 2 mA. How is to be modified to convert it to a voltmeter of 5 V range by connecting some resistance? |
1230 Ω connected in series with galvanometer 2460 Ω connected in series with galvanometer 1230 Ω connected in parallel with galvanometer 2460 Ω connected in parallel with galvanometer |
2460 Ω connected in series with galvanometer |
The correct answer is Option (2) → 2460 Ω connected in series with galvanometer To convert the moving coil galvanometer into a voltmeter of a given range, one need to connect a series resistance known as resistance multiplier. Desired voltage range, $V=I_f×R_{total}$ $⇒R_{total}=\frac{V}{I_f}=\frac{5}{0.002}=2500Ω$ $R_{total}=R_G+R_S$ [$R_G$ = Resistance of galvanometer] $2500=R_S+40$ $⇒R_S=2460Ω$ |