CUET Preparation Today
Solve the differential equation $\frac{dy}{dx} + y = x$. |
$xe^x - e^x + c $ $x- e^x + c $ $xe^x - 1 + c $ $xe^x +1 + c $ |
$xe^x - e^x + c $ |
The correct answer is Option (1) →$xe^x - e^x + c $ ## The given differential equation is of the form $\frac{dy}{dx} + Py = Q$. The integrating factor of the differential equation is $e^{\int dx} = e^x$. The solution of the differential equation is $ ye^x = \int xe^x dx + c $ $ = xe^x - e^x + c $ |
