Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Moving Charges and Magnetism

Question:

An electron beam moving with a speed of 2.5×107ms−1  enters into the magnetic field directed perpendicular to its direction of motion. The magnetic induction of the field is 4×10−3wb/m2. What is the intensity of the electric field applied so that the electron remains undeflected due to the magnetic field ?

Options:

10N/C

10N/C

10N/C

10N/C

Correct Answer:

10N/C

Explanation:

E = vB

v = 2.5×107ms−1 ; B = 4×10−3wb/m2

E = 10N/C