Diameter of a circle is 20 cm. Length of a chord AB is 10 cm. What will be the angle made by this chord at the center of this circle ?
Answer & explanation
Correct answer: option 3
Concept Used
Radius = \(\frac{Diameter}{2}\)
2. In an equilateral triangle, since the three sides are equal therefore the three angles, opposite to the equal sides are equal in measure.
Calculation
OA = OB = AB = 10 cm
\(\Delta \)OAB is an equilateral triangle.
So, \(\angle\)OAB = \(\angle\)OBA = \(\angle\)AOB = \(\frac{180}{3}\) = \({60}^\circ\)
Therefore, the angle made by this chord at the center of this circle = \({60}^\circ\).