The greatest possible value of 'a' such that the function $f(x) = x^2+ax + 1$ is always decreasing in the interval [1, 2], is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → -4
Given function:
$f(x) = x^{2} + ax + 1$
For $f(x)$ to be always decreasing on $[1,2]$:
$f'(x) \le 0$ for all $x \in [1,2]$
$f'(x) = 2x + a$
The derivative is largest at $x = 2$ .
So the condition must hold at $x = 2$:
$2(2) + a \le 0$
$4 + a \le 0$
$a \le -4$
Thus the greatest possible value of $a$ is:
$-4$