A person has some coins of ₹10, ₹5, and ₹2 denominations. The ratio of the products of the numbers of ₹10 and ₹5 coins, the numbers of ₹5 and ₹2 coins, and the numbers of ₹2 and ₹10 coins is 3 : 4 : 2 respectively. What could be the minimum amount of money this person has? |
₹52 ₹88 ₹68 ₹74 |
₹68 |
Ratio = 3 : 4 : 2, By multiplying with 6 we get, 18 : 24 : 12 We write 18 : 24 : 12 as (6 x 3) : (6 x 4) : (4 x 3) So from this we can assume the number of 10 rupee coins are 3, No. of 5 rupee coins are 6 and 2 rupee coins are 4. ⇒ (10 x 3) + (5 x 6) + (2 x 4) ⇒ 30 + 30 + 8 ⇒ Rs. 68. |