If $A$ and $B$ are matrices of same order, then $(AB' - BA')$ is a

skew-symmetric matrix

The correct answer is Option (1) → skew-symmetric matrix ##

We have matrices $A$ and $B$ of same order.

Let $P = (AB' - BA')$

Then, $P' = (AB' - BA')' = (AB')' - (BA')'$

$= (B')'(A') - (A')'(B) = BA' - AB'$

$= -(AB' - BA') = -P$

Since, $P' = -P$

Hence, $(AB' - BA')$ is a skew-symmetric matrix.