If $A$ and $B$ are matrices of same order, then $(AB' - BA')$ is a
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → skew-symmetric matrix ##
We have matrices $A$ and $B$ of same order.
Let $P = (AB' - BA')$
Then, $P' = (AB' - BA')' = (AB')' - (BA')'$
$= (B')'(A') - (A')'(B) = BA' - AB'$
$= -(AB' - BA') = -P$
Since, $P' = -P$
Hence, $(AB' - BA')$ is a skew-symmetric matrix.