If the length of diagonals of a rhombus are 10 cm and 24 cm then the side of the rhombus is.

13 cm

As per the above figture: Diagonals are AC and DB

ATQ, AC = 10cm, DB = 24cm

Note: In rhombus, Diagonals are always bisect each other at right angle.

O is the intersecting point of two diagonals, which bisects the diagonals at right angle.

Thus, AO = 5 cm, DO = 12cm

In ΔAOD (right angle triangle):

⇒ $AO^2 + OD^2 = AD^2$

$25 + 144 = AD^2$

AD = Side of rhombus = $\sqrt{169} = 13$ cm