For a party 7 guests are invited by a husband and his wife. They sit in a row for dinner. The probability that the husband and his wife sit together, is
Answer & explanation
Correct answer: option 2
The total number of ways in which 7 guests and the couple can sit in a row is 9!.
Number of ways in which the husband and his wife sit together is 2! × 8!
∴ Required probability $=\frac{2! × 8!}{9!}=\frac{2}{9}$