Practicing Success
the correct solution of the differential equation dy/dx = (1-cosx) / (1+cos x) is- |
y = 2 tan(x/2) + x +C y = -2 tan(x/2) - x +C y = 2tan(x/2) - x + 2+ C y = 2 tan (x/2) - x +C |
y = 2 tan (x/2) - x +C |
The given differential equation is dy/dx = (1-cosx) / (1+cos x) ⇒ dy/dx = 2 sin2(x/2) / 2 cos2(x/2) =tan2(x/2) ⇒ dy/dx = sec2(x/2) -1 separating the variables, we get dy ={ sec2(x/2) -1} dx Now, integrating both sides of the equation. we get: ∫dy = ∫{ sec2(x/2) -1} dx ⇒ y = 2tan(x/2) - x +C which is the solution of the given differential equation.
dy |