Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Probability

Question:

A pack of cards consists of 15 cards numbered 1 to 15. Three cards are drawn at random with replacement. Then, the probability of getting 2 odd and one even numbered cards is:

Options:

$\frac{348}{1125}$

$\frac{398}{1125}$

$\frac{448}{1125}$

$\frac{498}{1125}$

Correct Answer:

$\frac{448}{1125}$

Explanation:

P(odd card selected) = $\frac{8}{15}$, P (even card selected) = $\frac{7}{15}$

P(2 odd, 1 even) = ${^3C}_2.(\frac{8}{15})^2.\frac{7}{15}=\frac{448}{1125}$