Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electric Charges and Fields

Question:

Options:

a

b

c

d

Correct Answer:

d

Explanation:

$ V = \frac{q}{4\pi \epsilon_0 x_0}( 1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4}+ ........ \text{up to infinity})$

$V = \frac{q}{4\pi \epsilon_0 x_0} ln2$