If E, M, J and G denote energy , mass , angular momentum and gravitational constant then $\frac{EJ^2}{M^5G^2}$ has the dimensions of –
Answer & explanation
Correct answer: option 2
[E] = $[ML^2T^{-2}], [J] = [ML^2T^{-1}], [G] = [M^{-1}L^3T^{-2}]$
Dimension of $\frac{EJ^2}{M^5G^2} = \frac{[ML^2T^{-2}][ML^2T^{-1}]^2}{[M^5][M^{-1}L^3T^{-2}]^2} = [M^0L^0T^0]$