Practicing Success
The curve x = 4 – 3y – y2 cuts the y-axis into two points P and Q. Then the area enclosed by the y-axis and the portion of the curve which lies between P and Q is |
20 sq. units 18 sq. units 17 sq. units none of these |
none of these |
Required area = $\int\limits_{-4}^1x\,dy$ $=\int\limits_{-4}^1(4-3y-y^2) = 20\frac{5}{6}$ sq. units. Hence (D) is the correct answer. |