The curve x = 4 – 3y – y2 cuts the y-axis into two points P and Q. Then the area enclosed by the y-axis and the portion of the curve which lies between P and Q is
Answer & explanation
Correct answer: option 4
Required area = $\int\limits_{-4}^1x\,dy$
$=\int\limits_{-4}^1(4-3y-y^2) = 20\frac{5}{6}$ sq. units.
Hence (D) is the correct answer.