Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Application of Integrals

Question:

The curve x = 4 – 3y – y2 cuts the y-axis into two points P and Q. Then the area enclosed by the y-axis and the portion of the curve which lies between P and Q is

Options:

20 sq. units

18 sq. units

17 sq. units

none of these

Correct Answer:

none of these

Explanation:

Required area = $\int\limits_{-4}^1x\,dy$

$=\int\limits_{-4}^1(4-3y-y^2) = 20\frac{5}{6}$ sq. units.

Hence (D) is the correct answer.