If the length of a side of the square is equal to that of the diameter of a circle, then the ratio of the area of the square and that of the circle is: ($π =\frac{22}{7}$)
Answer & explanation
Correct answer: option 1
Let the length of the side of the square = x
then, also the diameter of the circle = x
Then, radius of the circle = \(\frac{x}{2}\)
The required ratio = x2 : π(\(\frac{x}{2}\))2
= x2 : \(\frac{22}{7}\) × \(\frac{x^2}{4}\)
= 28 : 22 = 14 : 11