If the length of a side of the square is equal to that of the diameter of a circle, then the ratio of the area of the square and that of the circle is: ($π =\frac{22}{7}$)

14 : 11

Let the length of the side of the square = x

then, also the diameter of the circle = x

Then, radius of the circle = \(\frac{x}{2}\)

The required ratio =  x² : π(\(\frac{x}{2}\))² 

= x² : \(\frac{22}{7}\) × \(\frac{x^2}{4}\)

= 28 : 22 = 14 : 11