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If two concentric circles are of radii 13 cm and 12 cm, respectively, then the length of the chord of the larger circle which touches the smaller circle is: |
35 cm 10 cm 15 cm 25 cm |
10 cm |
We know that, (Perpendicular)2 + (Base)2 = (Height)2 We have, OA = 13 cm and OM = 12 cm then, AM2 = 132 - 122 = 25 cm = AM = 5 cm AB = 5 + 5 = 10 cm |
