Practicing Success
If two concentric circles are of radii 13 cm and 12 cm, respectively, then the length of the chord of the larger circle which touches the smaller circle is: |
35 cm 10 cm 15 cm 25 cm |
10 cm |
We know that, (Perpendicular)2 + (Base)2 = (Height)2 We have, OA = 13 cm and OM = 12 cm then, AM2 = 132 - 122 = 25 cm = AM = 5 cm AB = 5 + 5 = 10 cm |