Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Average

Question:

The average mathematics marks of two sections A and B of class IX in the annual examination is 74. The average marks of section A is 77.5 and that of section B is 70. The ratio of the number of students of section A and B is:

Options:

7 : 8

7 : 9

8 : 7

8 : 9

Correct Answer:

8 : 7

Explanation:

If the number of students in section A be p and that in section B be q, then

According to question,

74 = \(\frac{ 75.5 \; × \; p\; + \;q \; × \; 70}{ p \; + \;q}\)

⇒ 74p + 74q = 77.5p + 70q

⇒ 77.5p – 74p = 74q – 70q

⇒ 3.5p = 4q

\(\frac{p}{q}\) =  \(\frac{8}{7}\)