While a collector to emitter voltage is constant in a transistor, the collector current changes by 8.2 mA when the emitter current changes by 8.3 mA. The value of forward current ratio is:
Answer & explanation
Correct answer: option 1
Here, $ΔE_E=8.3mA, ΔI_C= 8.2mA$
As $ΔI_E =ΔI_B+ΔI_C$
$∴ΔI_B = ΔI_E −ΔI_C = 8.3 mA – 8.2 mA = 0.1 mA$
Forward current ratio, $h_{fe}=[\frac{ΔI_C}{ΔI_B}]_{V_{CE\,is\,constant}}=[\frac{8.2mA}{0.1mA}]=82$