The price of an article, passing through three hands, rises on the whole by 61%. If the first and the second sellers earned 15% and 20% profit respectively, find the percentage profit earned by the third seller. |
16% $\frac{100}{6}\%$ 20% 12.5% |
$\frac{100}{6}\%$ |
The correct answer is Option (2) → $\frac{100}{6}\%$ To find the profit percentage of the third seller, we can use the concept of successive percentage increases. Step-by-Step Calculation: 1. Define the Initial Price: Let the initial cost price of the article be ₹100. 2. Calculate Price after the First Seller (15% Profit): $\text{Price}_1=100×(1+\frac{15}{100})=100×1.15=₹115$ 3. Calculate Price after the Second Seller (20% Profit): The second seller earns 20% profit on the price they paid (₹115). $\text{Price}_2=115×(1+\frac{20}{100})=115×1.20=₹138$ 4. Determine the Final Price (61% Overall Rise): The problem states that the price rises on the whole by 61% from the initial price. $\text{Final Price}=100×(1+\frac{61}{100})=₹161$ 5. Calculate the Third Seller's Profit: Let the third seller's profit percentage be x. The third seller bought the article for ₹138 and sold it for ₹161. $\text{Profit}=161−138=₹23$ $\text{Profit Percentage (x)}=(\frac{\text{ Profit }}{\text{Cost Price for 3rd seller}} )×100$ $x=(\frac{23}{138})×100$ 6. Simplify the Fraction: Divide both 23 and 138 by their greatest common divisor (which is 23): $23÷23=1$ $138÷23=6$ $x=\frac{1}{6}×100=\frac{100}{6}\%$ |