Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Compound Interest

Question:

Find compound interest in \(\frac{19}{7}\) years at the rate of 14% p.a. compounded annually, If the sum invested is Rs.10000/-.

Options:

Rs. 4250

Rs. 4295.6

Rs. 4856

Rs. 5000

Correct Answer:

Rs. 4295.6

Explanation:

\(\frac{19}{7}\) years = 2\(\frac{5}{7}\) years

Rate of interest for \(\frac{5}{7}\) years = \(\frac{5}{7}\) × 14% = 10%

14% = \(\frac{7}{50}\) and 10% =  \(\frac{1}{10}\) 

                             Principal             Sum

1st year                   50                   57       (for 2 years → R% = 14%)

2nd year                  50                   57       (for \(\frac{5}{2}\) years → R% = 10%)

(Int on int.)              10                   11   

Total                      25,000            35,739 

C.I. = 35739 - 25000 = 10,739

Principal = 25000R = 10000 (given)

1R = 0.4

Hence, C.I. = 10739 × 0.4 = 4295.6