"Calculate the cell potential Ecell at 25oC for the cell if the initial concentration of Ni(NO3)2 is 0.100 molar and initial concentration of AgNO3 is 1.00 molar. [ EoNi2+/ Ni = -0.25V; EoAg+/Ag= 0.80V]"
Answer & explanation
Correct answer: option 4
Ecell = Eocell - \(\frac{0.059}{2}\) log\(\frac{[Ni^{2+}]}{[Ag^+]^2}\)
Eocell = 0.80 + 0.25 = 1.05 V
Ecell = 1.05 - \(\frac{0.059}{2}\) log\(\frac{0.1}{1^2}\)
=1.05 - \(\frac{0.059}{2}\) x (-1) =1.05 + 0.0295
Ecell = 1.0795 V