For a reaction, 2A + 3B → C + 4D, the following expression log(-\(\frac{dA}{dt}\)) = log\(\frac{dD}{dt}\) + x is valid. What is the value of x?
Answer & explanation
Correct answer: option 2
2A + 3B → C + 4D
rate = -\(\frac{1}{2}\)\(\frac{dA}{dt}\) = -\(\frac{1}{3}\)\(\frac{dB}{dt}\) = +\(\frac{1}{1}\)\(\frac{dC}{dt}\) = +\(\frac{1}{4}\)\(\frac{dD}{dt}\)
-\(\frac{1}{2}\)\(\frac{dA}{dt}\) = +\(\frac{1}{4}\)\(\frac{dD}{dt}\)
-\(\frac{dA}{dt}\) = \(\frac{1}{2}\)\(\frac{dD}{dt}\)
log(-\(\frac{dA}{dt}\)) = log(\(\frac{1}{2}\)\(\frac{dD}{dt}\))
log(-\(\frac{dA}{dt}\)) = log(\(\frac{dD}{dt}\)) - log2
log(-\(\frac{dA}{dt}\)) = log(\(\frac{dD}{dt}\)) - 0.3
comparing with log(-\(\frac{dA}{dt}\)) = log\(\frac{dD}{dt}\) + x
x = -0.3