A body weighs 72 N on the surface of the earth. What is the gravitational force on it, at a height equal to half the radius of the earth?
Answer & explanation
Correct answer: option 4
W = \(\frac{W_o}{(1+\frac{h}{R})^2}\)
Put h = \(\frac{R}{2}\)
Wo = 72 N
W = 32 N