The points on the curve $\frac{x^2}{9}+\frac{y^2}{16}=1$ at which the tangents are parallel to x-axis are:

$(0, \pm 4)$ $(0,4)$ $(0,-4)$ $(0,0)$

$(0, \pm 4)$

The correct answer is Option (1) - $(0, \pm 4)$