Practicing Success
From a circle of radius 15 cm, a sector central angle 216° is cut and its bounding radii are joined without overlap so as to form a cone. Find its volume. |
1081.3 cm3 1071.3 cm3 1018.3 cm3 1061.9 cm3 |
1018.3 cm3 |
Here, radius of the circle R = 15 cm Where the sector is cut and its bounding radii is bent to form a cone. Slant height of the cone, l = R = 15 cm Let ‘r’ and ‘h’ be the radius and height of the cone respectively. Again, we know that in a circle of radius ‘R’, an arc of length ‘X’ subtends an angle of ‘θ’ radians. Then x = Rθ $⇒2πr=Rθ⇒\frac{r}{R}=\frac{θ}{2π}$ $⇒\frac{r}{15}=\frac{216}{360}$ ⇒ r = 9 cm Now, height of the cone can be calculated as $h^2=l^2-r^2$ $h^2=15^2-9^2=225-51=144$ h = 12 cm ∴ Volume of the cone, $V = \frac{1}{3}πr^2h$ $=\frac{1}{3}×\frac{22}{7}×81×12$ = 1018.28 cm3
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