CUET Preparation Today
If $(t_1, y_1), (t_2,y_2)......... (t_n, y_n)$ denote the time series and $y_t$ are the trend values of the variables y, then |
$\sum\limits_{i=1}^{n}(y_i-y_t) = 0$ $\sum\limits_{i=1}^{n}(y_i-y_t) = 1$ $\sum\limits_{i=1}^{n}(y_i-y_t) = ∞$ $\sum\limits_{i=1}^{n}(y_i-y_t) ≠ 0$ |
$\sum\limits_{i=1}^{n}(y_i-y_t) = 0$ |
The correct answer is Option (1) → $\sum\limits_{i=1}^{n}(y_i-y_t) = 0$ ** For a time series $(t_1,y_1),(t_2,y_2),\ldots,(t_n,y_n)$ with trend values $y_t$, the deviations from trend satisfy $\displaystyle \sum_{i=1}^{n}(y_i - y_t) = 0$. Correct option: $\displaystyle \sum_{i=1}^{n}(y_i - y_t)=0$ |
