Practicing Success
Practicing Success
CUET Preparation Today
The area enclosed by the curve $x=8 \cos t, y=4 \sin t$ between the lines $x=0$ and $x=4 \sqrt{3}$ is: |
$8 \sqrt{2}+\frac{32 \pi}{3}$ units $4 \sqrt{3}+\frac{16 \pi}{3}$ units $8 \sqrt{3}+\frac{32 \pi}{3}$ units $32 \pi$ units |
$8 \sqrt{3}+\frac{32 \pi}{3}$ units |
The correct answer is Option (3) - $8 \sqrt{3}+\frac{32 \pi}{3}$ units |
